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Question
A ring of radius 6 cm , mass 100 gm is kept at a distance of 8 cm from the origin. What will be the gravitational potential energy of the system, if a particle of mass 10 gm is kept at the origin
A ring of radius 6 cm , mass 100 gm is kept at a distance of 8 cm from the origin. What will be the gravitational potential energy of the system, if a particle of mass 10 gm is kept at the origin
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Solution
The correct option is C −6.67×10−13 J
The potential at the origin due to the ring of mass m and radius a distance r from the origin is given by −Gm/√(r2+a2).
In the problem, it is given that, a= 6 cm and r = 8 cm, m=100 gm. Substituting these parameters, we get, V=−6.67×10−11×0.1/0.1=−6.67×10−11
The potential energy of the system will be = mV=0.01×6.67×10−11=−6.67×10−13 J
The correct option is (c)
The potential at the origin due to the ring of mass m and radius a distance r from the origin is given by −Gm/√(r2+a2).
In the problem, it is given that, a= 6 cm and r = 8 cm, m=100 gm. Substituting these parameters, we get, V=−6.67×10−11×0.1/0.1=−6.67×10−11
The potential energy of the system will be = mV=0.01×6.67×10−11=−6.67×10−13 J
The correct option is (c)
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