wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

A ring of radius (R) carries a uniformly distributed charge +Q. A point charge q is placed on the axis of the ring at a distance 2R from the centre of the ring and released from rest. The particle

A
stays in rest
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
executes simple harmonic motion
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
executes oscillation but not SHM
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
moves to the centre of ring immediately and stays there
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C executes oscillation but not SHM
Net force due to ring at a point on axis for a particle having charge q is F=Qqx4πϵ0(R2+x2)3/2, acting towards centre of the ring.

Since the force is attractive, the particle will carryout a periodic motion with ring's centre as its mean position.

As F=KQqx(x2+R2)3/2 is not of form F=kx , oscillation is not in SHM.

flag
Suggest Corrections
thumbs-up
30
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Simple Harmonic Oscillation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon