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Standard XII

Physics

Towards Biot-Savart Law

A ring of rad...

Question

A ring of radius R is carrying uniformly distributed charge $+$ Q. A test charge $- q_{0}$ is placed on its axis at a distance $2$ R from the centre and released. The motion of the particle on the axis will be :

periodic

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non periodic

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simple haramonic

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random

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Solution

The correct option is A periodic

Since the force is attractive, the particle will carryout a periodic motion with ring's centre as its mean position.

and,

$F = \frac{- k Q q x}{(x^{2} + R^{2})^{\frac{3}{2}}}$ is not of the form $F = - k x$

Therefore the oscillations will not be simple harmonic.

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A ring of radius R is carrying uniformly distributed charge +Q. A test charge −q0 is placed on its axis at a distance 2R from the centre and released. The motion of the particle on the axis will be :

The correct option is A periodic Since the force is attractive, the particle will carryout a periodic motion with ring's centre as its mean position. and, F=−kQqx(x2+R2)32 is not of the form F=−kx Therefore the oscillations will not be simple harmonic.

A ring of radius R is carrying uniformly distributed charge $+$ Q. A test charge $- q_{0}$ is placed on its axis at a distance $2$ R from the centre and released. The motion of the particle on the axis will be :

The correct option is A periodic

Since the force is attractive, the particle will carryout a periodic motion with ring's centre as its mean position.

and,

$F = \frac{- k Q q x}{(x^{2} + R^{2})^{\frac{3}{2}}}$ is not of the form $F = - k x$

Therefore the oscillations will not be simple harmonic.