Question

A ring of radius $R$ rolls without sliding with a constant velocity with respect to ground. The radius of curvature of the path followed by any particle of the ring at the highest point of its path will be

• A. $R$
• B. $2R$
• C. $4R$
• D. None

Answer 1

Answer: (C)

$4R$

According to the given question
its based on acceleration in uniform circular motion
where,$a=\frac{v2}{R}$
$R^{\prime }=\frac{v2}{a}$
because body is present at the highest point than $v=2r\omega$
whereas $a=r\omega$
$R^{\prime }=4R$