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Pure Rolling

A ring of rad...

Question

A ring of radius R rolls without slipping on a rough horizontal surface with a constant velocity. The radius of curvature of the path followed by any particle of the ring at the highest point of its path will be :

A

5 R

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B

2 R

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C

4 R

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D

N o n e o f t h e s e

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Solution

The correct option is B $4 R$
Radius of Curvature
$= \frac{(v e l o c i t y)^{2}}{N o r m a l A c c e l e r a t i o n}$

$= \frac{(2 v)^{2}}{v^{2} / R} = 4 R$

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