A ring with a uniform charge Q and radius R, is placed in the y−z plane with its centre at the origin(k=14πε0). Then :
A
the field at the origin is not equal to zero
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B
the potential at the origin is kQR
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C
the field at the point (x,0,0) is kQx2
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D
the field at the point (x,0,0) is kQR2+x2
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Solution
The correct option is D the potential at the origin is kQR We know potential due to υ1 at a distance r1,v1=kv1r1 Now as Q is placed at distance R from centre ∴ Potential at the centre=kQ√R2=kQR