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Question

A ring with radius 4 m is hinged at point P. Two forces F1 and F2, each of magnitude 10 N acts on the Ring. Find the ratio of the torques produced by two forces F1 to F2 is


A

1:2

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B

2:1

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C

1:3

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D

3:1

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Solution

The correct option is B

2:1


Given,

Radius of ring r = 4 m

Force F1 = 10 N

Force F2 = 10 N

Torque due to force= Force × perpendicular distance between line of action of force and axis of rotation

Perpendicular distance of point of rotation P from the Force F1 is d1=8 m while that from force F2 is d2=4 m
Torque T1 produced by F1 = d1×F1 = 8×10 = 80 N m

Torque T2 produced by F2 = d2×F2 = 4×10 = 40 N m

Ratio of torques T1T2 = 21


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