A river flows due south with a speed of 2.0 m/s. A man steers a motorboat across the river; his velocity relative to the water is 4 m/s due east. The river is 800 m wide. What is his velocity relative to the earth? Assume North as positive y-direction.

$- 4^i + 2^j$

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$4^i + 2^j$

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$4^i - 2^j$

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$- 4^i - 2^j$

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Solution

The correct option is C
$4^i - 2^j$

${\to v}_{r i v e r} = - 2^j m / s, {\to v}_{m a n, r i v e r} = 4^i m / s$

${\to v}_{m r} = {\to v}_{m} - {\to v}_{r}$

$\Rightarrow {\to v}_{m} = {\to v}_{m r} + {\to v}_{r}$

= $4^i - 2^j$

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Similar questions

A river flows due south with a speed of 2.0 m/s. A man steers a motorboat across the river; his velocity relative to the water is 4 m/s due east. The river is 800 m wide. How much time is required to cross the river?

A river flows due south with a speed of 2.0 m/s. A man steers a motorboat across the river; his velocity relative to the water is 4 m/s due east. The river is 800 m wide. How far south of his starting point will be reach the bank?

Q. A river flows due south with a speed of

2.0 m s^{- 1}

. A man steers a motorboat across the river, his velocity relative to the water is

4 m s^{- 1}

due east. The river is

800

m wide.
a. What is his velocity (magnitude and direction) relative to the earth?
b. How much time is required to cross the river?
c. How far south of his starting point will he reach the opposite bank?

A boat moves relative to water with a velocity 'v' which is n times less than the river flow velocity u. At what angle to the north direction must the boat move to minimize drifting if the river flows from west to east?

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A river flows due south with a speed of 2.0 m/s. A man steers a motorboat across the river; his velocity relative to the water is 4 m/s due east. The river is 800 m wide. What is his velocity relative to the earth? Assume North as positive y-direction.

The correct option is C 4^i−2^j →vriver=−2^jm/s,→vman,river=4^im/s →vmr=→vm−→vr ⇒→vm=→vmr+→vr = 4^i−2^j

The correct option is C
$4^i - 2^j$

${\to v}_{r i v e r} = - 2^j m / s, {\to v}_{m a n, r i v e r} = 4^i m / s$

${\to v}_{m r} = {\to v}_{m} - {\to v}_{r}$

$\Rightarrow {\to v}_{m} = {\to v}_{m r} + {\to v}_{r}$

= $4^i - 2^j$