A river flows due south with a speed of 2.0 m/s. A man steers a motorboat across the river; his velocity relative to the water is 4 m/s due east. The river is 800 m wide. What is his velocity relative to the earth? Assume North as positive y-direction.

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Solution

The correct option is C

${\to v}_{r i v e r} = - 2^j m / s, {\to v}_{m a n, r i v e r} = 4^i m / s$

${\to v}_{m r} = {\to v}_{m} - {\to v}_{r}$

$\Rightarrow {\to v}_{m} = {\to v}_{m r} + {\to v}_{r}$

= $4^i - 2^j$

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A river flows due south with a speed of 2.0 m/s. A man steers a motorboat across the river; his velocity relative to the water is 4 m/s due east. The river is 800 m wide. What is his velocity relative to the earth? Assume North as positive y-direction.

A river flows due south with a speed of 2.0 m/s. A man steers a motorboat across the river; his velocity relative to the water is 4 m/s due east. The river is 800 m wide. How much time is required to cross the river?

A river flows due south with a speed of 2.0 m/s. A man steers a motorboat across the river; his velocity relative to the water is 4 m/s due east. The river is 800 m wide. How far south of his starting point will be reach the bank?

Q. A river flows due south with a speed of

2.0 m s^{- 1}

. A man steers a motorboat across the river, his velocity relative to the water is

4 m s^{- 1}

due east. The river is

800

m wide.
a. What is his velocity (magnitude and direction) relative to the earth?
b. How much time is required to cross the river?
c. How far south of his starting point will he reach the opposite bank?

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A river flows due south with a speed of 2.0 m/s. A man steers a motorboat across the river; his velocity relative to the water is 4 m/s due east. The river is 800 m wide. What is his velocity relative to the earth? Assume North as positive y-direction.

The correct option is C →vriver=−2^jm/s,→vman,river=4^im/s →vmr=→vm−→vr ⇒→vm=→vmr+→vr = 4^i−2^j

The correct option is C

${\to v}_{r i v e r} = - 2^j m / s, {\to v}_{m a n, r i v e r} = 4^i m / s$

${\to v}_{m r} = {\to v}_{m} - {\to v}_{r}$

$\Rightarrow {\to v}_{m} = {\to v}_{m r} + {\to v}_{r}$

= $4^i - 2^j$