A river flows due south with a speed of 2.0 m/s. A man steers a motorboat across the river; his velocity relative to the water is 4 m/s due east. The river is 800 m wide. How much time is required to cross the river?

187.6 s

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400 s

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173.91 s

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200 s

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Solution

The correct option is D
200 s

${\to v}_{m} = {\to v}_{m r} + {\to v}_{r} = 4^i - 2^j$

To calculate time, we need to consider only the horizontal displacement.

$∴ d = 800 m$

$∴ t = \frac{d_{x}}{v_{x}}$ is his horizontal component of velocity,

$∴ t = \frac{800}{4} = 200 s$

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A river flows due south with a speed of 2.0 m/s. A man steers a motorboat across the river; his velocity relative to the water is 4 m/s due east. The river is 800 m wide. How much time is required to cross the river?

A river flows due south with a speed of 2.0 m/s. A man steers a motorboat across the river; his velocity relative to the water is 4 m/s due east. The river is 800 m wide. How far south of his starting point will be reach the bank?

Q. A river flows due south with a speed of

2.0 m s^{- 1}

. A man steers a motorboat across the river, his velocity relative to the water is

4 m s^{- 1}

due east. The river is

800

m wide.
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b. How much time is required to cross the river?
c. How far south of his starting point will he reach the opposite bank?

A river flows due south with a speed of 2.0 m/s. A man steers a motorboat across the river; his velocity relative to the water is 4 m/s due east. The river is 800 m wide. What is his velocity relative to the earth? Assume North as positive y-direction.

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A river flows due south with a speed of 2.0 m/s. A man steers a motorboat across the river; his velocity relative to the water is 4 m/s due east. The river is 800 m wide. How much time is required to cross the river?

The correct option is D 200 s →vm=→vmr+→vr=4^i−2^j To calculate time, we need to consider only the horizontal displacement. ∴d=800m ∴t=dxvx is his horizontal component of velocity, ∴t=8004=200s

The correct option is D
200 s

${\to v}_{m} = {\to v}_{m r} + {\to v}_{r} = 4^i - 2^j$

To calculate time, we need to consider only the horizontal displacement.

$∴ d = 800 m$

$∴ t = \frac{d_{x}}{v_{x}}$ is his horizontal component of velocity,

$∴ t = \frac{800}{4} = 200 s$