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Question

A riveted joint, consisting of two identical rivets is subjected to an eccentric force 10 kN as shown in the figure. The primary and secondary shear loads on the rivet hole are respectively,


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Solution

Primary shear force in each rivet,

Ps1=P2=102 = 5 kN


Secondary shear force,

Ps2=Plr21+r22×r1=10×50×50(50)2+(50)2

= 5 kN

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