A road roller $4$ m wide and with a diameter of $3.5$ m makes $4$ revolutions in $1$ minute. How much time will it take to roll over an area of $6160$ m $^{2}$ ?

40

min

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20

min

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35

min

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17.5

min

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Solution

The correct option is C $35$ min
Area in one revolution $= 2 π r \times w i d t h = 2 π (\frac{3.5}{2}) \times 4$
$= \frac{22}{7} \times \frac{35}{10} \times 4 = 44 m^{2}$
No. of revolution required to roll area of 6160 m $^{2}$ $= \frac{6160}{44} = 140$
Time required $= \frac{140}{4} = 35 m i n$

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A road roller 4 m wide and with a diameter of 3.5 m makes 4 revolutions in 1 minute. How much time will it take to roll over an area of 6160 m2?

The correct option is C 35 minArea in one revolution =2πr×width=2π(3.52)×4 =227×3510×4=44m2No. of revolution required to roll area of 6160 m2 =616044=140Time required =1404=35min

A road roller $4$ m wide and with a diameter of $3.5$ m makes $4$ revolutions in $1$ minute. How much time will it take to roll over an area of $6160$ m $^{2}$ ?

The correct option is C $35$ min
Area in one revolution $= 2 π r \times w i d t h = 2 π (\frac{3.5}{2}) \times 4$
$= \frac{22}{7} \times \frac{35}{10} \times 4 = 44 m^{2}$
No. of revolution required to roll area of 6160 m $^{2}$ $= \frac{6160}{44} = 140$
Time required $= \frac{140}{4} = 35 m i n$