Question

A road roller takes $750$ complete revolutions to move once over to level a road. Find the area of the road if the diameter of a road roller is $84cm$ and lenght is $1m$.

Answer 1

Given $d=84cm,l=1m=100cm$

Curved surface area $=2\pi rl=2\times \frac{22}{7}\times 42\left(100\right)=26400c{m}^2$

Area covered in $1$ revolution of road roller $=26400c{m}^2$

Area covered by $750$ revolution $=26400\left(750\right)=19800000c{m}^2=1980m^2$