wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A road roller was used for levelling a road of width 2 m. It was observed that, the road roller required 25 complete revolutions to level the entire road. If the radius and the length of the roller is 7 m and 2 m respectively, then length of the road is ____. [Take π = 3.14].


A

1200 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

2100 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

1100 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

1234 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

1100 m


Given, Radius of Cylinder, r=7 m
length of roller, h=2 m
Width of road, B=2 m
Length of road be L
Number of revolution taken = 25

Roller rolls on its curved surface area.
Surface area of = CSA of cylinder
one revolution
=2πrh=2×227×7×2=88 m2

Total area covered in 25 revolution =25×88=2200 m2

This area will be equal to the area of the road levelled

Area of road = L×B=2200L×2=2200L=1100 m

Length of the level road is 1100 m.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon