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Question

A road runs parallel to a vertical cliff at a distance of 680m as shown in the figure. A truck, standing at P sounded the horn at an instance and the truck driver hears the echo after 4s. But the sound of the horn was heard twice by a person standing at Q within an interval of 2s. Give reasons why the person at Q heard the sound twice. Neglecting the wind velocity. Calculate how far the person was from the truck?
517904_337f8adcc57a46be867ecdd2bc8a3bbf.png

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Solution



Look at the modified diagram above.
The dark lines and the arrows show the directions in which sound travels from P to Q.
The 1st sound, which is heard by the person at Q, travels along the straight line PQ.
The second sound travels along the path POQ. Here the sound gets reflected at point O on the cliff.
The thin line OR is the Normal of the Reflection.
As the path POQ is longer than PQ, the 2nd sound reaches the person's ear 2 seconds later than the time when the 1st sound reached.
That is why the person heard the sound twice.

The driver heard an echo because the sound travelled along the perpendicular distance between the cliff and him, got relfected from the cliff, moved backwards along the same direction and reached his ear.
Thus the sound has travelled twice the distance 680m i.e. 1360m.
Since speed(v)=distancetime the speed of sound is v=6804=170m/s


PO2=PR2+OR2 ------------------------------------------(1)
where OR=680
Since PR=RQ,PQ=2PR and POQ=2PO
Time taken by the 1st sound to reach Q =PQv=2PRv
Time taken by the 2nd sound to reach Q =POQv=2POv
Since the time interval between hearing the 1st sound and the 2nd is 2 seconds, 2POv2PRv=2
POPR=v=170
PO=170+PR
Substituting in (1) we get
(170+PR)2=PR2+6802
1702+(2×170×PR)+PR2=PR2+6802
1702+340PR=6802
PR=68021702340=1275
PQ=2PR=2550metres

The person was 2550 metres away from the truck


674400_517904_ans_963ce593f2584aa68eca89b66983a3b0.png

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