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Question

A rocket is fired from the earth towards the sun. At what distance from the earth’s centre is the gravitational force on the rocket zero ? Mass of the sun = 2×10³⁰ kg, mass of the earth = 6×1024 kg. Neglect the effect of other planets etc. (orbital radius = 1.5 × 10¹¹ m).

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Solution

Given: The mass of the sun is 2× 10 30 kg, the mass of the earth is 6× 10 24 kg, the radius of orbit is 1.5× 10 11 m.

Let the distance from the center of the earth where the gravitational force is zero be x, then the distance from the sun will be rx.

The gravitational force on the rocket will be zero when the gravitational force due to earth is equal to the gravitational force due to sun.

Gm M s ( rx ) 2 = Gm M e x 2 ( r-x x ) 2 = M s M e

Where, the mass of the sun is M s , the mass of the earth is M e , the orbital radius is r, the mass of rocket is m.

By substituting the given values in the above expression, we get

( rx x ) 2 =( 2× 10 30 6× 10 24 ) 1.5× 10 11 x x =577.35 x=2.6× 10 8 m

Thus, the distance from the centre of the earth where gravitational force acting on rocket becomes zero is 2.6× 10 8 m.


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