A rocket is fired vertically from the ground- It moves upwards with a constant acceleration of 10 m-s2- After 30 seconds the fuel is finished- After what time from the instant of firing the rocket will it attain the maximum height- g-10 m-s2-

The correct option is A 30 s at t=30 secs v=at= 10× 30=300m/s as the fuel is done only g acts on the rocketat height h, v=0 v=0=300 gt t ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

General Gravity Problem

A rocket is f...

Question

A rocket is fired vertically from the ground. It moves upwards with a constant acceleration of $10 x m / s^{2}$ . After $30 x s e c o n d s$ the fuel is finished. After what time from the instant of firing the rocket will it attain the maximum height? $g = 10 x m / s^{2}$ :

30 s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

45 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

60 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

75 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $30 s$
at t=30 secs v=at= $10 \times 30 = 300 m / s$
as the fuel is done only g acts on the rocket
at height $h, v = 0$
$v = 0 = 300 - g t$
$t = 30 s e c s$
it will attain maximum height after a total time of 30 secs

Suggest Corrections

Similar questions

Q. A rocket is fired vertically from the ground. It moves upwards with a constant acceleration 10

m s^{- 2}

for 30 seconds, after which the fuel is consumed. After what time from the instant of firing, the rocket will attain the maximum height? (Take g = 10

m s^{- 2}

)

Q. A rocket, when fired, rises up with an acceleration of

20 m / s^{2}

for the first

1.0

minute. After this its fuel is finished and it goes on rising up just like a free body. Upto what maximum height will it rise? How much total time will it take before falling on earth?

(g = 10 m / s^{2})

Q. A rocket is fired and ascends with constant vertical acceleration of

10 m / s^{2}

for 1 minute. Its fuel is exhausted and it continues as a free particle.The maximum altitude reached is (

g = 10 m / s^{2}

)

Q. A rocket is fired vertically upwards with a net acceleration of 4

m / s^{2}

and initial velocity zero. After 5 s its fuel is finished and it decelerates with g. At the highest point its velocity becomes zero. Then it accelerates downwards with acceleration g and returns to ground. Plot velocity-time and displacement-time graphs for the complete journey.

A Rocket is launched to travel vertically upwards with a constant velocity of 20 m/s. After travelling for 35 seconds rocket develops a snag and its fuel supply is cut off. The rocket then travels like a free body. What is the total height achieved by it? After what time of its launch will it come back to the earth? ( g= 10 m/s²⁾

Join BYJU'S Learning Program

A rocket is fired vertically from the ground. It moves upwards with a constant acceleration of 10xm/s2. After 30xseconds the fuel is finished. After what time from the instant of firing the rocket will it attain the maximum height? g=10xm/s2:

The correct option is A 30 sat t=30 secs v=at=10×30=300m/sas the fuel is done only g acts on the rocketat height h,v=0v=0=300−gtt=30secsit will attain maximum height after a total time of 30 secs

A rocket is fired vertically from the ground. It moves upwards with a constant acceleration of $10 x m / s^{2}$ . After $30 x s e c o n d s$ the fuel is finished. After what time from the instant of firing the rocket will it attain the maximum height? $g = 10 x m / s^{2}$ :

The correct option is A $30 s$
at t=30 secs v=at= $10 \times 30 = 300 m / s$
as the fuel is done only g acts on the rocket
at height $h, v = 0$
$v = 0 = 300 - g t$
$t = 30 s e c s$
it will attain maximum height after a total time of 30 secs