wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A rocket is launched by the PSLV in which fuel capacity is 500 kg. The rocket consumes 2 kg fuel in 1 s. Find the time taken by the rocket to consume 300 kg fuel.

A
150 s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
300 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
100 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
50 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 150 s
Given, total mass of fuel M=500 kg
and rate of consumption of fuel
dMdt=2 kg/s
Integrating and taking the limits of fuel from 500 kg to 200 kg and time from 0 to t
200500dM=t02 kg/s dt
[M]200500=[2t]t0
300=2t
or t=150 s is the time taken to consume 300 kg fuel.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
How Do Rockets Fly in Space?
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon