A rocket is projected vertically upwards, whose time velocity graph is shown. The maximum height reached by the rocket is:

1 m

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10 m

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20 m

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55 m

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Solution

The correct option is D $55 m$
Maximum height is achieved when velocity becomes zero. Thus from this graph we can conclude that maximum distance is achieved at $t = 110$ s.
Maximum height $=$ Area under the curve from $t = 0$ to $t = 110$ , which is given as
$\frac{1}{2} \times 110 \times 1 = 55 m$

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A rocket is projected vertically upwards, whose time velocity graph is shown. The maximum height reached by the rocket is:

The correct option is D 55 mMaximum height is achieved when velocity becomes zero. Thus from this graph we can conclude that maximum distance is achieved at t=110 s.Maximum height = Area under the curve from t=0 to t=110, which is given as12×110×1=55m

The correct option is D $55 m$
Maximum height is achieved when velocity becomes zero. Thus from this graph we can conclude that maximum distance is achieved at $t = 110$ s.
Maximum height $=$ Area under the curve from $t = 0$ to $t = 110$ , which is given as
$\frac{1}{2} \times 110 \times 1 = 55 m$