A rod AB is shown in figure. End A of the rod is fixed on the ground. Block is moving with velocity √3m/s towards right. The velocity of end B of rod when rod makes an angle of 60∘ with the ground is
A
√3m/s
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B
2m/s
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C
2√3m/s
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D
3m/s
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Solution
The correct option is B2m/s As we take point B
From diagram we can say that
velocity of block can be given as v=vtcos30∘
where vt= velocity of point B as rod moves in circular trajectory
So √3=vt×√32⇒vt=2m/s