Question

A rod AB is shown in figure. End A of the rod is fixed on the ground. Block is moving with velocity. $\sqrt{3}$ m/s towards right. The velocity of end B of rod when rod makes an angle of ${60}^{\circ }$ with the ground is :

• A. $\sqrt{3}$
• B. $2m/s$
• C. $2\sqrt{3}$ m/s
• D. $3m/s$

Answer 1

The correct option is B $2m/s$

Here from the given figure we observe that the angle at point B will be ${30}^0$
Now resolve the component of velocity in both horizontal and vertical direction we find,

$V_x$cos${30}^0$=$\sqrt{3}$
$V_y$cos${30}^0=0$

Hence, velocity at point B =$\frac{\sqrt{3}}{cos{30}^0}$$=2m/s$