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Question

A rod AB is shown in figure. End A of the rod is fixed on the ground. Block is moving with velocity 3 m/s towards right. The velocity of end B of rod when rod makes an angle of 60 with the ground is


A
3 m/s
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B
2 m/s
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C
23 m/s
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D
3 m/s
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Solution

The correct option is B 2 m/s
As we take point B

From diagram we can say that
velocity of block can be given as
v=vtcos30
where vt= velocity of point B as rod moves in circular trajectory
So
3=vt×32vt=2 m/s

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