The correct option is B The end A becomes positively charged
Magnetic force F=q(→v×→B)=(−e)(v^i×(−B)^k)=−ebB^j where we have taken the charge of electron to be (-e) where e is positive. The direction of the magnetic field is taken to be −B^k i.e into the plane of the paper and velocity is taken along the +ve x-axis.
Thus electrons will move towards the end B and accumulate at end B.
Thus, the end A will become deficient in electrons and will be positively charged.