A rod AB of length 4 units moves horizontally with its left end A always on the circle x 2+y2-4x-18y-29=0 then the locus of the circle is
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Solution
We have x² + y²−4x−18y−29=0 As rod is of length of 4,and end A is on above circle and it moves horizontally,simiply replace x→x−4 to get locus of the circle. (x−4)²+ y²−4(x−4)−18y−29=0 ⇒ x²+16−8x+y²−4x+16−18y−29=0 ⇒ x²+y²−12x−18y+3=0 => ans
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