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A rod is fixe...

Question

A rod is fixed between two points at $20^{\circ}$ . The coefficient of linear expansion of material of rod is $\frac{1.1 \times 10^{- 5}}{^{\circ} C}$ and Young's modulus is $1.2 \times 10^{11} \frac{N}{m^{2}}$ . Find the stress developed in the rod if temperature of rod becomes $10^{\circ} C$

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Solution

The correct option is A
Thermal stress $\frac{F}{A} = Y α Δ θ = 1.2 \times 10^{11} \times 1.1 \times 10^{- 5} \times (20 - 10) = 1.32 \times 10^{7} \frac{N}{m^{2}}$

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