A rod is found to be 200 cm long at 40∘C and 200.24 cm at 100∘C. The coefficient of cubical expansion of the material is
A
2×10−5/∘C
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B
6×10−5/∘C
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C
3×10−5/∘C
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D
4×10−5/∘C
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Solution
The correct option is D6×10−5/∘C Change in length = (200.24 - 200)cm = 0.24 cm = 0.0024m So change in length = initial length x αΔT Here ΔT = 60K Initial length = 2m Putting all the values, we get α = 6 x 10−5