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Question

A rod is found to be 200 cm long at 40C and 200.24 cm at 100C. The coefficient of cubical expansion of the material is

A
2×105/C
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B
6×105/C
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C
3×105/C
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D
4×105/C
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Solution

The correct option is D 6×105/C
Change in length = (200.24 - 200)cm = 0.24 cm = 0.0024m
So change in length = initial length x αΔT
Here ΔT = 60K
Initial length = 2m
Putting all the values, we get α = 6 x 105

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