0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

# A rod is measured at 10∘C using a scale calibrated at that temperature. Find the percentage error in length, if thermal coefficients of linear expansion of the rod and scale are 3×10−5/∘C and 2×10−5/∘C respectively, and the rod is measured at 50∘C.

A
0.01 %
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.02 %
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.03 %
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.04 %
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D 0.04 %Let the length of the rod at temperature T0 [actual length] be L0 α0=3×10−5/∘C αs=2×10−5/∘C T0=10∘C T=50∘C Measured length at temperature T L=L0[1+(α0−αs)(T−T0)] Percentage error =(L−L0L0)×100 =[L0[1+(α0−αs)(T−T0)]−L0L0]×100 =[(α0−αs)(T−T0)]×100 =[(10−5)(40)]100 =4×10−2 =0.04 %

Suggest Corrections
0
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program