Question

A rod is of length 2 m and mass 1kg. What will be its moment of inertia about an axis perpendicular to its length and passing through one of its end?

• A. $\frac{4}{3}kg-m^2$
• B. $\frac{1}{3}kg-m^2$
• C. $\frac{3}{4}kg-m^2$
• D. $\frac{2}{3}kg-m^2$

Answer 1

The correct option is A $\frac{4}{3}kg-m^2$

$(M.I{)}_{rod}=\frac{M{L}^2}{3}$
$=\frac{(2{)}^2.1}{3}=\frac{4}{3}kg-m^2$