A rod of ferromagnetic material with dimension 10×0.5×0.2cm3 is placed in a magnetic field of strength 0.5×104Am−1 as a result of which a magnetic field of 5Am−2 is produced in the rod. The value of magnetic induction will be
A
0.358T
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B
0.54T
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C
6.28T
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D
2.519T
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Solution
The correct option is C6.28T Magnetization I=MV
Magnetic induction B=μ0(H+I)=μ0(H+MV)
Given : V=10×0.5×0.2cm3=10−6m3, M=5Am−2 and H=0.5×104Am−1 ∴B=4π×10−7(.5×104+510−6)=6.28T