A rod of lemgle2m and 0.5kg is fixed at one end and allowed to hang vertically from a rigid support. Find the work done in raising the other end of rod until it makes an angle 60° with the verticaverticaO:-)

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Solution

Since, if this is rotational setting where the factor of gravity works in the downward direction and support resists upward. For this reason, we have a torque of this scale:

Torque=(mh/2)g cos(60)

The work done in this case is calculated by integrating tangential force along the arc from 60 degrees to vertical.

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