You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Applying NLM along 3 Axis

A rod of leng...

Question

A rod of length $1.4 m$ and negligible mass has two masses of $0.3 k g$ and $0.7 k g$ tied to its two ends. Find the location of the point on this rod where the rotational energy is minimum where the rod is rotated about that point.

0.98 m

from

0.3 k g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.98 m

from

0.7 k g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.7 m

from

0.3 k g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.7 m

from

0.7 k g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $0.98 m$ from $0.3 k g$
By equating the moment about center of mass, let CM be $x$ distance from $0.3 k g$ mass. So distance from $0.7 k g$ mass is $1.4 - x$ .
So $0.3 x = 0.7 (1.4 - x) \Rightarrow x = 0.98 m$ (on balancing the torque)

Suggest Corrections

Similar questions

Q. Two point masses of 0.3 kg and 0.7 kg are fixed at the ends of a rod of length 1.4 m and of negligible mass.
The rod is set rotating about an axis perpendicular to its length with a uniform angular speed. The point on the
rod through which the axis should pass in order that the work required for rotation of the rod is minimum, is
located at a distance of

Q. Two point masses of

0.3 k g

and

0.7 k g

are fixed at the ends of a rod of length

1.4 m

and of negligible mass. The rod is set rotating about an axis perpendicular to its length with a uniform angular speed. The point on the rod through which the axis should pass in order that the work required for rotation of the rod is minimum is located at a distance of

Q. A thin rod of negligible mass and length 1.4 m has two point masses of 0.3. kg and 0.7 kg are fixed at its ends.
The rod is set rotating about an axis perpendicular to its length with a uniform angular speed. In order that the work required for rotation of the rod be minimum, the point on the rod through which the axis should pass, is located from the 0.3 kg mass at a distance of

Two point masses A of mass M and B of mass 4M are fixed at the ends of a rod of length l and of negligible mass. The rod is set rotating about an axis perpendicular to its length with a uniform angular speed. The work required for rotating the rod will be minimum when the distance of axis of rotation from the mass A is at

Q. Point masses

m_{1}

and

m_{2}

are placed at the opposite ends of a rigid rod of length L, and negligible mass. The rod is to be set rotating about an axis perpendicular to it. The position of point P on this rod through which the axis should pass so that the work required to set the rod rotating with angular velocity

ω_{0}

is minimum, is given by:

Join BYJU'S Learning Program

A rod of length 1.4m and negligible mass has two masses of 0.3kg and 0.7kg tied to its two ends. Find the location of the point on this rod where the rotational energy is minimum where the rod is rotated about that point.

The correct option is A 0.98m from 0.3kgBy equating the moment about center of mass, let CM be x distance from 0.3kg mass. So distance from 0.7kg mass is 1.4−x.So 0.3x=0.7(1.4−x)⇒x=0.98m (on balancing the torque)

A rod of length $1.4 m$ and negligible mass has two masses of $0.3 k g$ and $0.7 k g$ tied to its two ends. Find the location of the point on this rod where the rotational energy is minimum where the rod is rotated about that point.

The correct option is A $0.98 m$ from $0.3 k g$
By equating the moment about center of mass, let CM be $x$ distance from $0.3 k g$ mass. So distance from $0.7 k g$ mass is $1.4 - x$ .
So $0.3 x = 0.7 (1.4 - x) \Rightarrow x = 0.98 m$ (on balancing the torque)