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Question

A rod of length 4 m is placed along x-axis. The rod is non-uniform and the mass per unit length of rod varies as λ=x24x+4


then center of mass of rod is at

A
x=2 m
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B
x=3 m
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C
x=1 m
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D
x=1.5 m
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Solution

The correct option is A x=2 m
We have been given,
λ=x24x+4=(x2)2
If we draw the graph of λ vs x, we get


From the figure we can say that, the rod is non-uniform but load is symmetric about x=2 m, hence center of mass will be at x=2 m.

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