A rod of length 5 m is moving at a speed of 10m-s in a uniform magnetic field B - 3 - - 4 - - 2 k- T as shown in figure- Potential difference across the length of the rod is

Velocity of the rod is given by nbsp;v= 8 î + 6 ĵ. The magnietic field is nbsp;B = (3 î + 4 ĵ + 2 k̂) T The length of the rod is l = 4 î + 3 ĵ Potential diffe ...

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Standard XII

Physics

Motional EMF

A rod of leng...

Question

A rod of length 5 m is moving at a speed of 10m/s in a uniform magnetic field $\to B = (3^i + 4^j + 2^k) T$ as shown in figure. Potential difference across the length of the rod is

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Solution

The correct option is A 0V
Velocity of the rod is given by $\to v = 8^i + 6^j$ .
The magnietic field is $\to B = (3^i + 4^j + 2^k) T$
The length of the rod is $\to l = 4^i + 3^j$
Potential difference $= (\to v \times \to B) . \to l$
$(12^i - 16^j + 14^k) . (4^i + 3^j) = 0$

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A rod of length 5 m is moving at a speed of 10m/s in a uniform magnetic field →B=(3^i+4^j+2^k) T as shown in figure. Potential difference across the length of the rod is

The correct option is A 0VVelocity of the rod is given by →v=8^i+6^j. The magnietic field is →B=(3^i+4^j+2^k) T The length of the rod is →l=4^i+3^j Potential difference =(→v×→B).→l (12^i−16^j+14^k).(4^i+3^j)=0

A rod of length 5 m is moving at a speed of 10m/s in a uniform magnetic field $\to B = (3^i + 4^j + 2^k) T$ as shown in figure. Potential difference across the length of the rod is

The correct option is A 0V
Velocity of the rod is given by $\to v = 8^i + 6^j$ .
The magnietic field is $\to B = (3^i + 4^j + 2^k) T$
The length of the rod is $\to l = 4^i + 3^j$
Potential difference $= (\to v \times \to B) . \to l$
$(12^i - 16^j + 14^k) . (4^i + 3^j) = 0$