A rod of length 8 cm is cut into 5 equal pieces; 4 such pieces would be of length cm.

\frac{32}{5}

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\frac{8}{5}

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\frac{4}{5}

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Solution

The correct option is A $\frac{32}{5}$
Given,
Length of rod = 8 cm

Since, the 8-cm rod is cut into 5 equal pieces, length of each piece $= \frac{8}{5}$ cm

Therefore, the length of 4 pieces $= \frac{8}{5} \times 4 = \frac{32}{5}$ cm

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A rod of length 8 cm is cut into 5 equal pieces; 4 such pieces would be of length cm.

The correct option is A 325Given, Length of rod = 8 cm Since, the 8-cm rod is cut into 5 equal pieces, length of each piece =85 cm Therefore, the length of 4 pieces =85×4=325 cm

The correct option is A $\frac{32}{5}$
Given,
Length of rod = 8 cm

Since, the 8-cm rod is cut into 5 equal pieces, length of each piece $= \frac{8}{5}$ cm

Therefore, the length of 4 pieces $= \frac{8}{5} \times 4 = \frac{32}{5}$ cm