A rod of length l and radius r is joined to a rod of length l/2 and radius r/2 of same material. The free end of small rod is fixed to a rigid base and the free end of larger rod is given a twist of θo, the twist angle at the joint will be
A
θ/4
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B
θ/2
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C
5θ/6
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D
8θ/9
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Solution
The correct option is D8θ/9 r=C.θ=πηr4θ2L=constant ⇒πηr4(θ−θ0)2l=πη(r/2)4(θ0−θ′)2(l/2) ⇒(θ−θ0)2=θ016⇒θ0=89θ