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Magnetic Force on Moving Charge

A rod of leng...

Question

A rod of length $l$ carrying current $i$ is kept in uniform magnetic field of magnitude $B$ is shown in figure. Then the force on rod due to magnetic field is:

A

zero

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B

i l B s i n θ

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C

i l B c o s θ

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D

i l B

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Solution

The correct option is B $i l B s i n θ$
Force on a current carrying conductor is $F = \int i (\to d l \times \to B) = i l B sin θ^n$ where $^n$ is the vector perpendicular to the plane formed by length $l$ and magnetic field vector.

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