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Other
Quantitative Aptitude
Lines and Angles
A rod of leng...
Question
A rod of length ‘l’ slides with its ends on two perpendicular lines. Then the locus of its midpoint is
A
x
2
+
y
2
=
l
2
4
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B
x
2
+
y
2
=
l
2
2
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C
x
2
−
y
2
=
l
2
4
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D
x
2
−
y
2
=
l
2
3
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Solution
The correct option is
A
x
2
+
y
2
=
l
2
4
The correct answer is option (a). Check the video for the approach.
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Similar questions
Q.
A rod PQ of length 2a slides with its ends on the axes the locus of the circum-centre of
Δ
OPQ is
Q.
If
L
1
and
L
2
are the length of the tangent from
(
0
,
5
)
to the circles
x
2
+
y
2
+
2
x
−
4
=
0
and
x
2
+
y
2
−
y
+
1
=
0
then
Q.
A rod of length
3
l
units, slides with its ends
A
and
B
on the
x
and
y
axes respectively. Then the locus of the centroid of
△
O
A
B
is
(Here,
O
is the origin.)
Q.
If the curves
x
2
a
2
+
y
2
b
2
=
1
and
x
2
l
2
−
y
2
m
2
=
1
cut each other orthogonally, then
Q.
Two parabolas
y
2
=
4
a
(
x
−
l
1
)
and
x
2
=
4
a
(
y
−
l
2
)
always touch one another, the quantities
l
1
and
l
2
are both variable. Locus of their point of contact has the equation
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