You visited us 1 times! Enjoying our articles? Unlock Full Access!

Derivation of Position-Velocity Relation by Graphical Method

A rod of mass...

Question

A rod of mass $m$ and length $2 R$ is fixed the diameter of the ring of same mass $m$ and radius $R$ as shown in figure. The combined body is rolling without slipping along x-axis. Then the angular momentum about $x - a x i s$ is having magnitude equal to

2 m R v

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 m R v

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{10 m R v}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{11 m R v}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $2 m R v$
The net mass of the system is $2 m$
its velocity = $v$ (velocity of COM)
$\to L = M_{n e t} R \times v_{C O M} 2 m R \times v = 2 m R v$

Suggest Corrections

Similar questions

Q. A rod of mass

m

and length

2 R

is fixed along the diameter of a ring of same mass

m

and radius

R

as shown in figure.The combined body is rolling without slipping along x-axis. Find the angular momentum about z-axis.

A rod of mass m and length 2R is fixed along the diameter of a ring of same mass m and radius R as shown in figure. The combined body is rolling without slipping along x – axis. The angular momentum about z – axis is

Q. A disc of mass

M

and radius

R

is rolling without slipping with angular speed

ω

on a horizontal plane as shown in figure. The magnitude of angular momentum of the disc about the

x -

axis is:

Q. A solid sphere of mass m and radius

R

is rolling without slipping as shown in figure. Find angular momentum of the sphere about z-axis.

Q. A disc of mass

M

and radius

R

is rolling without slipping with angular speed

ω

on a horizontal plane as shown in figure. The magnitude of angular momentum of the disc about the origin

O

is:

Join BYJU'S Learning Program

A rod of mass m and length 2R is fixed the diameter of the ring of same mass m and radius R as shown in figure. The combined body is rolling without slipping along x-axis. Then the angular momentum about x−axis is having magnitude equal to

The correct option is A 2mRvThe net mass of the system is 2mits velocity =v(velocity of COM)→L=MnetR×vCOM2mR×v=2mRv

A rod of mass $m$ and length $2 R$ is fixed the diameter of the ring of same mass $m$ and radius $R$ as shown in figure. The combined body is rolling without slipping along x-axis. Then the angular momentum about $x - a x i s$ is having magnitude equal to

The correct option is A $2 m R v$
The net mass of the system is $2 m$
its velocity = $v$ (velocity of COM)
$\to L = M_{n e t} R \times v_{C O M} 2 m R \times v = 2 m R v$