wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A rod of mass m and length l is lying along the y-axis such that its end is at the origin. Suddenly an impulse is given to the rod such that immediately after the impulse, the end on the origin has a velocity v0^i and the other end has a velocity 2vo^i. The magnitude of angular momentum of the rod about the origin at this instant is 5nmv0l. Find n.

Open in App
Solution

Angular velocity of rod ω=2v0v0l=vol

Velocity of CoM of the rod
vcm=2v0+v02=32v0

Therefore angular momentum of rod about the origin
L=mvcm(l2)+Iendω
=m(l2)×32v0+ml212×v0l
=mv0l[34+112]=56mv0l

Thus the value of n is 6.


flag
Suggest Corrections
thumbs-up
2
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon