A rod of mass M and length L is standing on frictionless horizontal surface vertically. With slight disturbance it starts to fall. When rod is making angle of 37∘ with vertical,
A
Speed of center of mass is gL3
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B
Angular velocity of rod is √15g13L
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C
Velocity of center of mass is vertically downwards
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D
Speed of point of contact with ground is √12gL65
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Solution
The correct option is D Speed of point of contact with ground is √12gL65
By conservation of energy, ⇒mgL2(1−45)=12Iw2
where I=1375mL2 is about IAR
mgL10=12.1375mL2w2
⇒w=√15g13L
Since there is no horizontal force COM moves in vertical direction.