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Byju's Answer
Standard XI
Physics
The Complete Equilibrium
A rod of mass...
Question
A rod of mass
m
is placed on two supports as shown. Calculate the normal reaction of each support.
A
N
1
=
1
3
m
g
,
N
2
=
2
3
m
g
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B
N
1
=
2
3
m
g
,
N
2
=
1
3
m
g
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C
N
1
=
m
g
2
,
N
2
=
m
g
2
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D
N
1
=
m
g
4
,
N
2
=
3
m
g
4
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Solution
The correct option is
A
N
1
=
1
3
m
g
,
N
2
=
2
3
m
g
As th rod is in equilibrium,
∵
τ
A
=
0
∴
(
N
1
×
0
)
+
(
N
2
×
3
L
4
)
−
(
m
g
×
L
2
)
=
0
N
2
=
2
3
m
g
As,
N
1
+
N
2
=
m
g
and
N
1
=
1
3
m
g
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