Question

A rod of mass \(m\) of length \(l\) is rotating about a fixed point on the ceiling. Its angular velocity is \(\omega\) with respect to vertical axis as shown in the figure. The rod maintains a constant angle \(\theta\) with the vertical..


What is the rate of change of angualr momentum of hte rod with respect to the point of suspension?

• A. $\frac{m{\omega }^2{l}^2\sin \theta }{6}$
• B. $\frac{m{\omega }^2{l}^2\sin 2\theta }{6}$
• C. $\frac{m{\omega }^2{l}^2{\sin }^2\theta }{6}$
• D. $\frac{m{\omega }^2{l}^2{\cos }^2\theta }{6}$

Answer 1

The correct option is B $\frac{m{\omega }^2{l}^2\sin 2\theta }{6}$

$\overrightarrow{\tau }=\frac{d\overrightarrow{L}}{dt}$