Question

A rod PQ of length $\ell$ is rotating with angular velocity $\omega$ about its mid-point, in a uniform magnetic field B which is perpendicular to the plane of rotation of the rod. Find the induced emf between PQ. ?

• A. $\frac{B\omega {\ell }^2}{2}$
• B. $\frac{B\omega {\ell }^2}{4}$
• C. $B\omega {\ell }^2$
• D. $Zero$

Answer 1

The correct option is D $Zero$


$em{f}_{PC}=\frac{B\omega {\ell }^2}{8}em{f}_{CQ}=\frac{B\omega {\ell }^2}{8}em{f}_{PQ}=0$