A rod PQ of mass 'm' and length 'l' rotated about and axis through 'p' as shown in figure.Find the moment of inertia about axis of Rotation
A
3g2L
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B
ml23
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C
ml23cos2θ
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D
ml23+ml2
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Solution
The correct option is A3g2L Torqueontherod=momentofweightoftherodaboutPT=mgL2−−−(1)Momentofinertiaofrodabout,p=ML23−−−(2)Fromequation(1)and(2),wegetMgL2=ML23α∴α=3g2L