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Web Crippling

A rolled I - ...

Question

A rolled I - section beam is supported on a 100 mm side bearing plate. Thickness of the flange and web of the I - section are 18 mm and 8 mm respectively. Root radius of the I - section is 10 mm. As per IS : 800 - 2007, the web bearing strength (in kN, rounded off to two decimal place) of the beam is _____.
$(f_{y} = 250 M P a, γ_{m_{0}} = 1.10)$
309.09

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Solution

The correct option is A 309.09
$r = 10 m, t_{f} = 18 mm, t_{w} = 8 mm$

Effective area in bearing
$= [100 + 2.5 (t_{f} + r)] \times t_{w}$
$= [100 + 2.5 (18 + 10)] \times 8$
$= 1360 m m^{2}$

$Web bearing strength = A \frac{f_{y}}{γ_{m 0}}$

$= 1320 \times \frac{250}{1.10} \times 10^{- 3}$

$= 309.09 k N$

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