wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A rolled I-section beam is supported on a 75 mm wide bearing plate as shown in the figure. Thickness of flange and web of the I-section are 20 mm and 8 mm, respectively. Root radius of I-section is 10 mm. Assuming:

material yield stress, fy=250 MPa and
partial safety factor for material, γmo=1.10


As per IS: 800-2007, the web bearing strength (in kN, round off to 2 decimal places) of the beam is _____.

Open in App
Solution



Effective area in bearing=[75+2.5(flange thickness + root radius)]×8
=[75+2.5(20+10)]×8
=1200 mm2
So, web bearing strength=Agfy1.1

=1200×2501.1×103

=272.73 kN

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Web Crippling
OTHER
Watch in App
Join BYJU'S Learning Program
CrossIcon