A roller is pushed with a force of 100 N along its handle .Which is at an angle of 30 $^{o}$ with the horizontal .Find the work done in moving it through 10 m.

\sqrt{3}

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\sqrt{3}

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5000

\sqrt{3}

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500

\sqrt{3}

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Solution

The correct option is B 500 $\sqrt{3}$ J
Given : $F = 100 N$ $θ = 30^{o}$ $S = 10 m$
Work done $W = F S cos θ$
Or $W = 100 \times 10 \times cos 30^{o} = 100 \times 10 \times \frac{\sqrt{3}}{2}$
$⟹ W = 500 \sqrt{3} J$

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A roller is pushed with a force of 100 N along its handle .Which is at an angle of 30o with the horizontal .Find the work done in moving it through 10 m.

The correct option is B 500√3 JGiven : F=100 N θ=30o S=10 mWork done W=FScosθOr W=100×10×cos30o=100×10×√32⟹ W=500√3 J

A roller is pushed with a force of 100 N along its handle .Which is at an angle of 30 $^{o}$ with the horizontal .Find the work done in moving it through 10 m.

The correct option is B 500 $\sqrt{3}$ J
Given : $F = 100 N$ $θ = 30^{o}$ $S = 10 m$
Work done $W = F S cos θ$
Or $W = 100 \times 10 \times cos 30^{o} = 100 \times 10 \times \frac{\sqrt{3}}{2}$
$⟹ W = 500 \sqrt{3} J$