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Question

A room contains 35 kg of dry air and 0.5 kg of water vapor. The total pressure and temperature of air in the room are 100 kPa and 25C respectively. Given that the saturation pressure for water at 25C, is 3.17 kPa, the relative humidity of the air in the room is

A
67%
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B
55%
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C
83%
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D
71%
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Solution

The correct option is D 71%
ma=35kg;mv=0.5kg

ω=mvma=0.535=0.01428

also ω=0.622pvpa

pt=100kPa

ω=0.622pvptpv

Now,
0.01428=0.622pv100pv

pv=2.238kPa

Relative humidity,

ϕ=pvpvs=2.2383.17×100

=70.6%71%

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