Question

Question 106

A room is 4.5 m long and 4 m wide. The floor of the room is to be covered with tiles of size 15 cm by 10 cm. Find the cost of covering the floor with tiles at the rate of Rs 4.50 per tile.

Answer 1

Given, length of room = 4.5 m, width of room = 4 m and size of tiles $=15cm\times 10cm$
$\because$ Area of room $=l\times b=4.5\times 4=18m^2=18\times (100{)}^{2}c{m}^2=180000c{m}^2[\because 1m=100cm]$
$\therefore$ Area of 1 tile $=15\times 10=150c{m}^2$
So, number of tiles $=\frac{Areaofroom}{Areaof1tile}=\frac{180000}{150}=1200$
$\therefore$ Cost of covering the floor with tiles = Rs. $4.50\times 1200$ = Rs.5400