Question

A room is 6 m long, 4 m broad and 3 m high. Find the cost of laying tiles on its floor and four walls at the cost of Rs. 80/m${}^2$.

Answer 1

Area $=2h(l+b)$
We have, $l=6$m; $b=4$m; $h=3$m
Therefore, Area $=2$ x $3$ $(6+4)$ = $6\left(10\right)=60m^2$
Therefore, the area of four walls is $60m^2$
Now, we have find the area of the floor $=(l\times b)=(6\times 4)=24m^2$
Thus, area of floor + area of $4$ walls$=$ $60m^2$ + $24m^2$

$=84m^2$

Thus, the cost of laying tiles on its floor and its four walls at the rate of $Rs.$$80/m^2$

$=84\times 80$

$=6720Rs$.